If `(x^(2)-x)/(1-ax)` attains all real values `(x in R)` then possible value of a are
(A) `(-oo, 1)`
(B) `(1, oo)`
(C) `(1, oo)`
(D) (1, 2)

If e^x+e^(f(x))=e , then the range of f(x) is (-oo,1] (b) (-oo,1) (1, oo) (d) [1,oo)

If the difference between the roots of the equation x^2+""a x""+""1""=""0 is less than sqrt(5) , then the set of possible values of a is (1) (-3,""3) (2) (-3,oo) (3) (3,oo) (4) (-oo,-3)

If the difference between the roots of the equation x^(2)+ax+1=0 is less than sqrt(5) , then the set of possible values of a is (i) (3,oo) (ii) (-oo,-3) (iii) (-3,3) (iv) (-3,oo)

Find the values of 1/x for the following values fo x: (a) (2,5) " (b) "[-5,-1) " (c ) "(3,oo) (d) (-oo,-2] " (e ) "[-3,4]

If cos^2x-(c-1)cosx+2cgeq6 for every x in R , then the true set of values of c is (a) (2,oo) (b) (4,oo) (c) (-oo,-2) (d) (-oo,-4)

x^2/(r^2-r-6)+y^2/(r^2-6r+5)=1 will represent ellipse if r lies in the interval (a).(- oo ,2) (b). (3, oo ) (c). (5, oo ) (d).(1, oo )

The function f(x)=cot^(-1)x+x increases in the interval (a) (1,\ oo) (b) (-1,\ oo) (c) (-oo,\ oo) (d) (0,\ oo)

The domain of f(x)="log"|logx|i s (0,oo) (b) (1,oo) (c) (0,1)uu(1,oo) (d) (-oo,1)

The values of x for which 1/(1+sqrt(x)), 1/(1-x), 1/(1-sqrt(x) are in A.P. lie in the interval (A) (0,oo) (B) (1,oo) (C) (0,1) (D) none of these

"I f"(x)={((e^x-1)xsinx)/(x^n),x >0 0,x=0 is derivable at x=0 then interval of possible values of ' n ' is [1,oo) (b) (-oo,1] (-oo,2] (d) [1,2]