The kinetic energy k of a particle moving along a circle of radius R depends on the distance covered s as k=a `s^2` where a is a constant. The force acting on the particle is

The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as K.E = KS2 where K is a constant. Find the force acting on the particle as a function of S -

The kinetic energy of a particle moving along a circle of radius R depends on the distance covered S as K =alpha.S^(2), where alpha is a constant. Find the force acting on the particle as a function of S.

(a) A ball, suspended by a thread, swings in a vertical plane so that its acceleration in the extreme and the lowest positions are equal. The angle θ of thread deflection in the extreme position will be ( b) The kinetic energy of a particle moving in a circle of radius R depens on the distance covered as T = as^(2) , where 'a' is a constant. Find the force acting on the particle as a function of s.

The kinetic energy K of a particle moving along a circle of radius R depends upon the distance S as K=betaS^2 , where beta is a constant. Tangential acceleration of the particle is proportional to

The kinetic energy K of a particle moving along a circle of radius R depends upon the distance s as K=as^2 . The force acting on the particle is

For a particle moving on a curved path kinectic energy is given as k=AS where S is distance moved and A is constant quantity .Net force acting on particle is

A particle travels along the arc of a circle of radius r . Its speed depends on the distance travelled l as v=asqrtl where 'a' is a constant. The angle alpha between the vectors of net acceleration and the velocity of the particle is

A point object moves along an arc of a circle of radius 'R'. Its velocity depends upon the distance covered 'S' as V = Ksqrt(S) where 'K' is a constant. If ' theta' is the angle between the total acceleration and tangential acceleration, then

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass m is revolving in a horizontal circle of radius r under a centripetal force k//r^(2) where k is a constant. What is the total energy of the particle ?