If the average mass of a smoke particle in an indian kitchen is `4times10^(-17)` kg, the rms speed of the smoke particles at `27^o` C is approximately

Uncertainty in position of a hypothetical subatomic particle is 1 "Å" and uncertainty in velocity is (3.3)/(4 pi) xx 10^(5) m/s then the mass of the particle is approximately ( h = 6.6 xx 10^(-34) Js) :

Ratio of the average speed of He and SO_2 at 27^o C will be

Maximum speed of a particle in simple harmonic motion is v_(max) . Then average speed of this particle in one time period is equal to

Compare the mass of the sun with that of the Jupiter, if the mass of the Sun is approximately 2xx10^(30) kg and mass of the Jupiter is approximately 2xx10^(27) kg.

A time varying force acts on a particle of mass 5 kg as shown in figure . Find the speed of the particle, in m/s , after 10 s , if particle was intially at rest .

A particle of mass m moving towards west with speed v collides with another particle of mass m movies towards south. If two particles st ich t o each other the speed of the new particle of mass 2 m will be

Position-time graph for a particle moving along x- direction is as shown in the figure. Average speed of the particle from t = 0 to t = 4 is :

At what temperature will the particles in a sample of helium gas have an rms speed of 1.0 km//s ?

Time period of a particle in shm depends on the force constant k and mass m of the particle T = 2pisqrt(m/k) A simple pendulum executes shm approximately. Why then is the time period of a pendulum independent of a mass of the pendulum?

A particle of mass 10^31 kg is moving with a velocity equal to 10^5ms^-1 . The wavelength of the particle is equal to