Home
Class 12
PHYSICS
A test charge 1*6times10^(-19)C is movin...

A test charge `1*6times10^(-19)`C is moving with velocity `vec v=(2i+3j)m/sec` in a magnetic field `vec B=(2i+3j)Wb/m^(2)` .The magnetic force on the test charge

Promotional Banner

Similar Questions

Explore conceptually related problems

An alpha particle moving with the velocity vec v = u hat i + hat j ,in a uniform magnetic field vec B = B hat k . Magnetic force on alpha particle is

A charged particle moves with velocity vec v = a hat i + d hat j in a magnetic field vec B = A hat i + D hat j. The force acting on the particle has magnitude F. Then,

A charged particle moves with velocity vec v = a hat i + d hat j in a magnetic field vec B = A hat i + D hat j. The force acting on the particle has magnitude F. Then,

When a charged particle moving with velocity vec v is subjected to a magnetic field of induction vec B , the force on it is non-zero. This implies that:

A particle with charge -5.60 nC is moving in a uniform magnetic field vec B = -(1.25T) hat k. The magnetic force on the particle is measured to be vec F = -(3.36 xx 10^-7 N) hat i + (7.42 xx 10^-7 N) hat j. a. Calculate all components of the velocity of the particle from this information. b. Are there components of the velocity that cannot be determined by the measurement of the force? Explain. c. Calculate the scalar product vec v . vec F. What is the angle between v and F?

A particle with charge 7.00 mu C is moving with velocity vec v =- (4xx10^3 ms^-1) hat j. The magnetic force on the particle is measured to be vec F = +(8.4 xx 10^-2 N) hat i - (5.60 xx 10^-2 N) hat k. a. Calculate all the components of the magnetic field you can from this information. b. Are there components of the magnetic field that cannot be determined by measurement of the force? Explain. c. Calculate the scalar product vec B. vec F. What is the angle between vec B and vec F ?

A magnetic field vec(B) = B_(0)hat(j) , exists in the region a ltxlt2a , and vec(B) = -B_(0) hat(j) , in the region 2a lt xlt 3a , where B_(0) is a positive constant . A positive point charge moving with a velocity vec(v) = v_(0) hat (i) , where v_(0) is a positive constant , enters the magnetic field at x= a . The trajectory of the charge in this region can be like

A charge q=-4 mu C has an instantaneous velocity vec v = (2 hat i - 3 hat j + hat k)xx10^6 ms^-1 in a uniform magnetic field vec B = (2 hat i + 5 hat j - 3hat k)xx10^-2 T. What is the force on the charge?

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N If the coordinates of the particle at t = 0 are (2 m, 1 m, 0), coordinates at a time t = 3 T, where T is the time period of circular component of motion. will be (take pi = 3.14 )

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N Motion of charged particle will be along a helical path with