`int _(-1)^(1) (x-[x]) dx`

The value of the integral int_(-1)^(1) (x-[2x]) dx,is

Solve: int_(-1)^(1)x tan^(-1)x dx

The value of int_(-1)^(1)(x|x|)dx is equal to

Evaluate: int(x-1)/((x+1)(x-2))\ dx

int_(1)^(2) (1)/(x(1+x))dx

The value of the integral int_(0)^(1) x(1-x)^(n)dx is -

The integral int_(-1)^(1) (|x+2|)/(x+2)dx is equal to

If [] and { } represents greatest integar function and fractional function then int_(-1)^(1)([x]+{x}+|x|)dx equals

Evaluate int_(-1)^(1) log ((2-x)/( 2+x)) dx

int _(1)^x 1/x dx =