`2(cos ^2 theta - sin ^2 theta)=1`

2 cos ^(2) theta - 2 sin ^(2) theta =1, then theta =

If theta lies in the first quadrant and cos^2 theta - sin^2 theta = 1/2 then the value of tan^2 2 theta + sin^2 3 theta is:

Prove each of the following identities : (i) (1- tan^(2) theta)/(1+ tan^(2) theta) = ( cos^(2) theta - sin^(2) theta) (ii) (1- tan^(2) theta)/(cot^(2) -1) = tan^(2) theta

Evaluate 2(cos^2theta-sin^2theta)=1

Solve for theta : cos^2 theta-sin^2 theta=1/2,0 यदि cos^2 theta-sin^2 theta=1/2,0

Show that (cos^(2)theta - sin^(2)theta)=(2tan theta)/((1- tan^(2)theta)) is not an identity .

If 0^(@) lt theta lt 90^(@) and cos^(2) theta - sin^(2) theta = (1)/(2) , then what is the value of theta ?

If 0^(@) lt theta lt 90^(@) and cos^(2) theta - sin^(2) theta = 1/2 ,then value of theta is?

If theta lies in the first quadrant and cos^2 theta-sin^2 theta=1/2 , then the value of tan^2 theta+sin^2 3 theta is : यदि theta पहले चतुर्थाश में स्थित है और cos^2 theta-sin^2 theta=1/2 है, तो tan^2 theta+sin^2 3 theta का मान ज्ञात करें |