If A=[[1,2,3],[2,3,4],[3,4,5]], then 2A'...

If A=`[[1,2,3],[2,3,4],[3,4,5]]`, then `2A'-A=`_
(A)`[[1,2,3],[2,3,6],[3,3,7]]`
(B)`[[-1,0,3],[4,5,6],[7,-8,1]]`
(C)`[[1,5,3],[-2,4,0],[5,7,8]]`
(D)None of these

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