In a particular experiment, `272.8gm` of `P_(4)` reacted with excess of oxygen to form `P_(4)O_(10)` in `90%` yield. In the second step of the reaction, a `98%` yield of `H_(3)PO_(4)` was obtained. What mass of `H_(3)PO_(4)` was obtained?

Phospheric acid (H_(3)PO_(4)) perpared in two step process . (1) P_(4)+5O_(2) to P_(4)O_(10)" "(2) P_(4)O_(10) + 6H_(2)O to 4H_(3)PO_(4) Well allow 62 g of phosphrous to react with exces oxygen which from P_(4)O_(10) in 85% yield . In the sep (2) reaction 90% yield of H_3)PO_(4) is obtained . Mass of H_(3) PO_(4) produced is :

Phosphoric acid (H_3PO_4) prepared in a two step process. (1) P_4+5O_2rarrP_4 O_10 (2) P_4 O_10+6H_2Orarr4H_3 PO_4 We allow 62g of phosphorus to react with excess oxygen which form P_4 O_10 in 85% yield. In the step (2) reaction 90% yield of H_3PO_4 is obtained. mass of H_3PO_4 produced is :

27 gm of Al reacts with excess of oxygen to give 4.59 gm of Al_(2)O_(3) . Calculate percentage yield of reaction.

What is the basicity of H_(3)PO_(4) ?

Which of the following reaction does not produce H_(3)PO_(4) ?

In the reaction, H_3PO_4+Ca(OH)_2rarrCaHPO_4+2H_2O, the equivalent mass of H_3PO_4 is

The addition of NaH_(2)PO_(4) to 0.1M H_(3)PO_(4) will cuase

H_(3)PO_(2)+CuSO_(4) to Cu darr+H_(3)PO_(4)+HNO_(3)

Oxidation of Cu_(3)P " to " CuSO_(4) " and " H_(3)PO_(4) involves the loss of

The true statement of the acids of phosphorus H_(3)PO_(2),H_(3)PO_(3) and H__(3)PO_(4) is :