`(dy)/(dx)+2xy=x+y`

(dy)/(dx) + 2xy = x , given that y =1 when x =0

Find the particular solution of the differential equation (1 - x ^(2) ) (dy)/(dx) - xy = x ^(2) , given that y = 2 when x = 0 .

General solution of (dy)/(dx)=2xy+4x-3y-6 is log(y+2)=

a(x(dy)/(dx)+2y)=xy(dy)/(dx)

Solve (x^(2) + y^(2))(dy)/(dx) = 2xy

The solution of ((dy)/(dx))^(2) + (2x + y) (dy)/(dx) + 2xy = 0 , is

x^(2)(dy)/(dx)+y^(2)=xy

(dy)/(dx)=(2xy)/(x^(2)-y^(2))

The solution x^2( dy )/( dx) = x^2 + xy + y^2 is :

(dy)/(dx) = (2xy)/(x^(2)-1-2y)