The density of 3M sodium thiosulphate is 1.25 g/ml. Identify the correct statements from the following
A) % by weight of sodium thiosulphate is 37.92
B) The mole fraction of sodium thiosulphate is 0.065
C) The molarity of `Na^+` is 2.53 & `S_2O_3^-` is 1.25
D) Both (A) & (B)

The density of 3 M aqueous solution of sodium thiosulphate is 1.25 g/mL. Calculate (i) mole fraction of sodium thiosulphate (ii) molalities of Na^+ and S_(2)O_(3)^(2-) ions.

Which of the followingg statements are true about sodium thiosulphate, Na_(2)S_(2)O_(3) ?

The density of 3 M solution of Na_2S_2O_3 is 1.25g/mL . What is % by weight of Na_2S_2O_3 ?

The density of a 3 M Na_(2) S_(2) O_(3) (sodium thiosulphate) solution is 1.25 g mL^(-1) . Calculate: a. % by weight of Na_(2) S_(2) O_(3) b. Mole fraction of Na_(2) S_(2) O_(3)

Sodium thiosulphate, Na_(2)S_(2)O_(3).5H_(2)O is used in photography to

The density of a 3 M Na_(2) S_(2) O_(3) (sodium thiosulphate) solution is 1.25 g mL^(-1) . Calculate: a. % by weight of Na_(2) S_(2) O_(3) b. Mole fraction of Na_(2) S_(2) O_(3) c. Molalities of Na^(o+) and S_(2) O_(3)^(2-) ions.

Sodium thiosulphate, Na_(2)S_(2)O_(3)*5H_(2)O is used in photography to:

632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) Moles of sodium thiosulophate reacted and unreacted after the reaction are respectively,

In the test for iodine, I_(2) is treated with sodium thiosulphate (Na_(2)S_(2)O_(3)) : Na_(2)S_(2)O_(3)+I_(2) to NaI +..

Both sodium sulphate (Na_(2)SO_(4)) and sodium sulphite (Na_(2)SO_(3)) are the compounds of sodium, sulphur and oxygen. By calculations prove that the quantity of oxygen in sodium sulphate is greater than that in sodium sulphite. (R.A.M. : Na = 23, S = 32, O = 16.]