Vapour pressure

An ideal mixture of liquids A and B with 2 moles of A and 2 moles of B has a total vapour pressure of 1 atm at a certain temperature. Another mixture with 1 mole of A and 3 moles of B has a vapour pressure greater than 1 atm. But if 4 moles of C are added to second mixture, the vapour pressure comes down to 1 atm. Vapour pressure of C, P_(C)^(@)=0.8 atm. Calculate the vapour pressure of pure A and B :

The vapour pressure of water at 293 K is 17.51 mm . The lowering of vapour pressure of sugar is 0.0614 mm . Calculate: a. The relative lowering of vapour pressure b.The vapour pressure of the solution c. The mole fraction of water

Assertion:Lowering of vapour pressure is not dependent on the number of species present in the solution. Reason : Lowering of vapour pressure and relative lowering of vapour pressure are colligative properties

Mole fraction of component A in vapour phase is chi_(1) and that of component A in liquid mixture is chi_2 , then ( p_(A)^@ )= vapour pressure of pure A, p_(B)^@ = vapour pressure of pure B), the total vapour pressure of liquid mixture is

Mole fraction of component A in vapour phase is chi_(1) and that of component A in liquid mixture is chi_2 , then ( p_(A)^@ )= vapour pressure of pure A, p_(B)^@ = vapour pressure of pure B), the total vapour pressure of liquid mixture is

At 300 K, the vapour pressure of an ideal solution containing 1 mole of A and 3 moles of B is 500 mm Hg. At the same temperature, 2 moles of B are added to this solution. The vapour pressure of solution increases by 10% of the original vapour pressure. Correct statements about the vapour pressure are

The vapour pressure of pure liquids A and B is 450 and 700mm Hg , respectively, at 350K. Find out the composition of the liquid mixture if the total vapour pressure is 600mm Hg . Also find the composition of the vapour phase.

At 298K , the vapour pressure of pure liquid n-butane is 1823 torr and vapour pressure of pure n-pentane is 521 torr and form nearly an ideal solution. a. Find the total vapour pressure at 298 K of a liquid solution containing 10% n-butane and 90% n-pentane by weight, b. Find the mole fraction of n-butane in solution exerting a total vapour pressure of 760 torr. c. What is composition of vapours of two components (mole fraction in vapour state)?

At 27^(@)C .the vapour pressure of an ideal solution containing 1 mole of A and 1 mole and B is 500 mm of Hg . At the same temperature, if 2 mol of B is added to this solution the vapour pressure of solution increases by 50 mm of Hg . The vapour pressure of A and B in their pure states is respectively.

Two liquids A and B are mixed to form an ideal solution. The totol vapour pressure of the solution is 800 mm Hg. Now the mole fractions of liquid A and B are interchanged and the total vapour pressure becomes 600 mm of Hg. Calculate the vapour pressure of A and B in pure form. (Given : p_(A)^(@)-p_(B)^(@)=100 )