Raoult's law

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . The mole fraction of A in the solution, if it obeys Raoult's law, is:

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . The mole fraction of A in the solution, if it obeys Raoult's law, is:

(a) State Raoult's law for a solution containing volatile components. How does Raoult' s law become a special case of Henry's law? (b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (K_(f)" for benzene "=5.12 kg mol^(-1))

Answer the question (given below) which are based on the following diagra. Consider some facts about the above phase diagram : Vapour pressure diagram for real solutions of two liquids A and B that exhibit a positive deviation from Raoult's law. The vapour pressure of both A and B are greater than predicted by Raoult's law. The dashed lines lines represented the plots for ideal solutions. A : This is observed when A...B attraction are greater than average of A...B and B...B attraction: B : DeltaH_("mix")=+ve,DeltaV_("mix")=+ve C : Boiling point is smaller than expected such that vaporisation is increased D : Mixture is called azeotropic mixture Select correct facts

Answer the question (given below) which are based on the following diagra. Consider some facts about the above phase diagram : Vapour pressure diagram for real solutions of two liquids A and B that exhibit a positive deviation from Raoult's law. The vapour pressure of both A and B are greater than predicted by Raoult's law. The dashed lines lines represented the plots for ideal solutions. Total vapour pressure of mixture of 1 mol of volatile component A(P_(A)^(@)=100 mmHg) and 3 mol of volatile component B(P_(B)^(@)=60 mmHg) is 75 mm . For such case:

The total vapour pressure of a 4 mole % solution of NH_(3) in water at 293 K is 50.0 torr. The vapour pressure of pure water is 17.0 torr at this temperature . Applying Henry's and Raoult's law, calculate the total vapour pressure for a 5 mole % solution:

If two liquids A(boiling point= t_1°C )and B(boiling point= t_2°C ) on mixing forms azeotropic solution which shows positive deviation from Raoult's law, then boiling point of azeotropic solution will be [Given,t1>t2]

Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point (T_(b)) of pure acetone is less than that of pure CS_(2) . Pick out the incorrect statement among the following :