A particle is executing SHM about `y=0` along y-axis. Its position at an instant is given by `y=(7m)sin(pi t)` .Its average velocity for a time interval `0` to `0.5s` is
(1) `14m/s`
(2) `7m/s`
(3) `(1)/(7)m/s`
(4) `28 m/s`

A particle is executing SHM about y =0 along y-axis. Its position at an instant is given by y = (7m) sin (pit) . Its average velocity for a time interval 0 to 0.5 s is

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

The velocity (v) - time (t) graph for a particle moving along x -axis is shown in the figure.The average velocity in the time interval t=0 to t=8s is 1) 4.5m/s 2) 2.5m/s 3) 5m/s 4) 2m/s

The velocity (v) - time (t) graph for a particle moving along x -axis is shown in the figure.The average velocity in the time interval t=0 to t=8s is 1) 4.5m/s 2) 2.5m/s 3) 5m/s 4) 2m/s

A particle executing SHM along y-axis, which is described by y = 10 "sin"(pi t)/(4) , phase of particle at t =2s is

A particle moves in a straight line. Its position ( in m) as function of time is given by x = (at^2 + b) What is the average velocity in time interval t = 3s to t = 5s in ms^(-1) . (where a and b are constants and a = 1ms^(-2), b = 1m ).

The particle is executing SHM on a line 4 cm long. If its velocity at mean position is 12 m/s , then determine its frequency.

A particle is projected from ground at angle 45^@ with initial velocity 20(sqrt2) m//s . Find (a) change in velocity, (b) magnitude of average velocity in a time interval from t=0 to t=3s .

A particle is executing SHM on a straight line. A and B are two points at which its velocity is zero. It passes through a certain point P(APltBP) at successive intervals of 0.5s and 1.5 s with a speed of 3m/s.

Time period of a particle executing SHM is 16s.At time t = 2s , it crosses the mean position . Its amplitude of motion is ( 32sqrt(2))/(pi) m . Its velocity at t = 4s is