Pronoun Basic to Advance PART - 3 एक जबरदस्त क्लास English Grammar For All Competitive Exams

Sentence : Type & Parts || Day 1 || Class 10 English Grammar || UP Board Exam 2022

State weather the statement is true/False? (i) If A is set of all positive factors of 36, then A={1,2,3,4,6,9,12,18,36} (in roaster form) and A={x: x is factor of 36, x in N} (in set builder form) (ii) If A is set of vowels in English alphabet then A={a,e,I,o,u} (in roaster form) and A={x:x is a vowels in English alphabet} {in set-builder form}

The "competitive edge" of a baseball team is defined by the formula sqrt(W/L) , where W represents the number of the team's wins and L represents the number of the team's losses. This year, the GMAT All-Stars had 3 times as many wins and one-half as many losses as they had last year. By what factor did their "Competitive edge" increase ?

STATEMENT - 1 : H_(2)S in acidic medium is the group reagent for II^(nd) group in basic radical. STATEMENT - 2 : K_(sp) of suphides of II^(nd) group ions is less. STATEMENT - 3 : All sulphides of II^(nd) group element are coloured.

Amines are derivatives of ammonia and are classified as 1^(@), 2^(@) , and 3^(@) , Primary and secondary (but not teritiary amines) form intermolecular hydrogen bonds and thus they boil at highter temperatures than expected. Like ammonia, all amines are basic, although they differ in their basic nature. As amines are considered as derivatives of ammonia, quaternary ammonium salts are considered as derivatives of ammonium salts. Only the quaternary ammonium salts can shown optical activity. When nitrogen is bounded to three different groups

Amines are derivatives of ammonia and are classified as 1^@, 2^@ , and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia, all amines are basic, although they differ in their basic nature.As amines are considered as derivatives of ammonia, quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity. Which of the following statement is correct ?

Amines are derivatives of ammonia and are classified as 1^@, 2^@ , and 3^@ Primary and secondary (but not teritary amines) form intermolecular hydrogen bonds and thus they boil at higher temperature than expected.Like ammonia, all amines are basic, although they differ in their basic nature.As amines are considered as derivatives of ammonia, quatemary ammonium salts are considered as derivatives of ammonium salts.Only the quatemary ammonium salts can show optical activity. Methylethylpropyl amine is optically inactive because

If a statement is true for all the values of the variable, such statements are called as identities. Some basic identities are : (1) (a+b)^(2)=a^(2)+2ab+b^(2)=(a-b)^(2)+4ab (3) a^(2)-b^(2)=(a+b)(a-b) (4) (a+b)^(3)=a^(3)+b^(3)+3ab(a+b) (6) a^(3)+b^(3)=(a+b)^(3)=3ab(a+b)=(a+b) (a^(2)-ab) (8) (a+b+c)^(2)=a^(2)+b^(2)+c^(2)+2ab+2bc+2ca=a^(2)+b^(2)+c^(2)+2abc((1)/(a)+(1)/(b)+(1)/(c)) (10) a^(3)+b^(3)+c^(3)-3abc=(a+b+c)(a^(2)+b^(2)+c^(2)-ab-bc-ca) =1/2(a+b+c)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)] If a+b+c=0,thena^(3)+b^(3)+c^(3)=3abc If a,b, c are real and distinct numbers, then the value of ((a-b)^(3)+(b-c)^(3)+(c-a)^(3))/((a-b).(b-c).(c-a))is

If a statement is true for all the values of the variable, such statements are called as identities. Some basic identities are : (1) (a+b)^(2)=a^(2)+2ab+b^(2)=(a-b)^(2)+4ab (3) a^(2)-b^(2)=(a+b)(a-b) (4) (a+b)^(3)=a^(3)+b^(3)+3ab(a+b) (6) a^(3)+b^(3)=(a+b)^(3)=3ab(a+b)=(a+b) (a^(2)-ab) (8) (a+b+c)^(2)=a^(2)+b^(2)+c^(2)+2ab+2bc+2ca=a^(2)+b^(2)+c^(2)+2abc((1)/(a)+(1)/(b)+(1)/(c)) (10) a^(3)+b^(3)+c^(3)-3abc=(a+b+c)(a^(2)+b^(2)+c^(2)-ab-bc-ca) =1/2(a+b+c)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)] If a+b+c=0,thena^(3)+b^(3)+c^(3)=3abc If (a+(1)/(a))^(2)=3, "then" a^(3)+(1)/(a^(3)) equats :

If a statement is true for all the values of the variable, such statements are called as identities. Some basic identities are : (1) (a+b)^(2)=a^(2)+2ab+b^(2)=(a-b)^(2)+4ab (3) a^(2)-b^(2)=(a+b)(a-b) (4) (a+b)^(3)=a^(3)+b^(3)+3ab(a+b) (6) a^(3)+b^(3)=(a+b)^(3)=3ab(a+b)=(a+b) (a^(2)-ab) (8) (a+b+c)^(2)=a^(2)+b^(2)+c^(2)+2ab+2bc+2ca=a^(2)+b^(2)+c^(2)+2abc((1)/(a)+(1)/(b)+(1)/(c)) (10) a^(3)+b^(3)+c^(3)-3abc=(a+b+c)(a^(2)+b^(2)+c^(2)-ab-bc-ca) =1/2(a+b+c)[(a-b)^(2)+(b-c)^(2)+(c-a)^(2)] If a+b+c=0,thena^(3)+b^(3)+c^(3)=3abc If x,y, z are different real umbers and (1)/((x-y)^(2))+(1)/((y-z)^(2))+(1)/((z-x)^(2))=((1)/(x-y)+(1)/(y-z)+(1)/(z-x))^2+lamda then the value of lamda is