`(sin3 theta)/(sin theta)-(cos3 theta)/(cos theta)`=2

(sin 3 theta)/(sin theta)-(cos 3 theta)/(cos theta)= A) sin 2 theta B) cos 4 theta C)1D)2

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .

The value of the expression ((sin 3theta)/sin theta)^2-((cos3theta)/cos theta)^2=

((sin3 theta)/(sin theta))^(2)-((cos3 theta)/(cos theta))^(2)=a cos2 theta wherever it id defined.Then the value of a is

The value of the expression ((sin3 theta)/(sin theta))^(2)-((cos3 theta)/(cos theta))^(2) when theta=7.5^(@)

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=lambda[(Tan mu theta)-Tan theta]" then "mu-50 lambda =

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)

(sin3 theta-sin theta)/(cos theta-cos3 theta)=cot2 theta

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=