What is the normal B.P. of an aqueous solution whose freezing point is `-2.48^(o)C`?
`(K_(f)=1.86^(o)C.kg.mol^(-1), K_(b)=0.512^(o)C.kg.mol^(-1))`

Complete the following statements by selecting the correct alternative from the choices given : An aqueous solution of urea freezes at - 0.186^(@)C, K_(f) for water = 1.86 K kg. mol^(-1),K_(b) for water = 0.512 "K kg mol"^(-1) . The boiling point of urea solution will be :

An aqueous solution freezes at -0.2^(@)C . What is the molality of the solution ? Determine also (i) elevation in the boiling point (ii) lowering in vapour pressure at 25^(@)C , given that K_(f)=1.86^(@)C" kg mol"^(-1), K_(b)=0.512^(@)C" kg mol"^(-1) , and vapour pressure of water at 25^(@)C is 23.756 mm.

An aqueous solution freezes at -0.186^(@)C (K_(f)=1.86^(@) , K_(b)=0.512^(@) . What is the elevation in boiling point?

For an aqueous solution freezing point is -0.186^(@)C . The boiling point of the same solution is (K_(f) = 1.86^(@)mol^(-1)kg) and (K_(b) = 0.512 mol^(-1) kg)

An aqueous solution of 0.1 molal concentration of sucrose should have freezing point (K_(f)=1.86K mol^(-1)kg)

How many moles of sucrose should be dissolved in 500gms of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point. (K_(f)=1.86 K Kg "mol"^(-1).K_(b)=0.52K Kg "mol"^(-1))

Elevation in boiling point of a solution of non-electrolyte in CCl_(4) is 0.60^(@)C . What is the depression in freezing point for the same solution? K_(f)(CCl_(4)) = 30.00 K kg mol^(-1), k_(b)(CCl_(4)) = 5.02 k kg mol^(-1)

An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given K_(f)=1.86 K kg "mol"^(-1) , K_(b)=0.512 K kg "mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following. Depression in freezing point of solution

An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given K_(f)=1.86 K kg "mol"^(-1) , K_(b)=0.512 K kg "mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following. Boiling point of the solution is

An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given K_(f)=1.86 K kg "mol"^(-1) , K_(b)=0.512 K kg "mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following. Molality of the solution is