Home
Class 12
PHYSICS
A dielectric slab of dimensions l timesl...

A dielectric slab of dimensions `l timesl` and thickness d is inserted between plates of a parallel plate capacitor of dimensions `l times2l` and taken out. with a constant velocity v. Separation between the plates of capacitor is d. Whole arrangement is shown in the figure. The variation of current (i) through the circuit as function of time t can be qualitatively represented as Neglect resistance of connecting wires and internal resistance of battery and assume that at t=0 the slab is just out side the capacitor

Promotional Banner

Similar Questions

Explore conceptually related problems

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

A slab of copper of thickness y is inserted between the plates of parallel plate capacitor as shown in figure. The separation between the plates is d. If y=d/4 , then the ratio of capacitance of the capacitor after nd before inserting the slab is

A dielectric slab of area A and thickness d is inderted between then plates of a capaitor of area 2A with constant speed upsilon as shown in. Dustance between the plates is (d). . The capacitor is connected to a battery of emf E . The current in the ciruit varies with time as.

The' distance between the plates of a parallel plate capacitor is d . A metal plate of thickness d//2 is placed between the plates. What will e its effect on the capacitance.

In a parallel-plate capacitor of plate area A , plate separation d and charge Q the force of attraction between the plates is F .

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

A slab of copper of thickness b is inserted in between the plates of parallel plate capacitor as shown in figure. The separation of the plate is d . If b=d//2 , then the ratio of capacities of the capacitor after and before inserting that slab will be

If a dielectric slab of thickness t and area A is inserted in between the plates of a parallel plate capacitor of plate area A and distance between the plates d(d gt t) then find out capacitance of system. What do you predict about the dependence of capacitance on location of slab?

Two thin dielectric slabs of dielectric constants K_(1) and K_(2) (K_(1) lt K_(2)) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by

A dielectric slab of length l, width b, thickness d and dielectric constant K fills the space inside a parallel plate capacitor. At t = 0, the slab begins to be pulled out slowly with speed y. At time t, the capacity of the capacitor is