`lim_(x->0) (4^x-1)/(2x)`

Use formula lim_(x->0)(a^x-1)/x=log(a) to find lim_(x->0)(2^x-1)/((1+x)^(1/2)-1)

Evaluate lim_(xto0) (e^(x)-1-x)/(x^(2)).

lim_(x->0)((4^x+9^x)/2)^(1/x)

lim_(xrarr0)(4^x-1)/(3^x-1) equals

Evaluate: lim_(x->0) (1-cos2x)/(x^2)

The value of lim_(x->0)(1-1/2^x)(1/(sqrt(tanx+4)-2))

lim_(x->oo) ((x^2-2x+1)/(x^2-4x+2))^x is equal to

Let f''(x) be continuous at x = 0 and f"(0) = 4 then value of lim_(x->0)(2f(x)-3f(2x)+f(4x))/(x^2)

lim_(x→0) (√(x+1)−1)/x

(i) lim_(x to 0) (a^(x) - 1)/(log_(a)(1 + x)), a gt 0 (ii) lim__(x to 0) (In (X + a)- In a)/(e^(2x) - 1) (ii) lim_(x to (pi)/(4)) (In(tanx))/(1 - cotx)