`B_2` molecule will be diamagnetic when (1) S-P mixing is not operative (2) S-P mixing is operative & Hund's rule is violated (3) S-P mixing is operative & Hund's rule is not violated.

Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule C_(2) is :

Assuming 2s-2p mixing is NOT operative, the paramagnetic species among the following is .

Which is incorrect regarding S and P mixing (along Z axis.) ?

A p-n-p transistor is said to be in active region of operation, When

If Hund' s rule is violated then how many unpaired electrons are present I n [Cr(NH_(3))_(6)]^(3+) complex ion ? .

Comprehension # 1 Read the following rules and answer the questions at the end of it. Electrons in various suborbits of an filled in increasing order to their energies. Pairing of electrons in various orbitals of a suborbit takes places only after each orbital is half-filled. No two electrons in an atom can have the same set of quantum number. While writing the following electronic configuration of Fe some rules have been violated : I : Aufbau's rule, II : Hund's rule III : Pauli's exclusion principle

Statement-I : The configuration of B atom cannot be 1s^(2) 2s^(3) . Because Statement-II : Hund's rule demands that the configuration should display maximum multiplicity.

If nitrogen atoms had electronic configuration 1s7 It would have energy lower than that of the nornal ground state configuration 1s^(2) 2s^(2) 2p^(3) because the electrons would be clear to the nucleus yet 1s^(7) is not oberved because it violates ?

If nitrogen atoms had electronic configuration 1s^(7) It would have energy lower than that of the normal ground state configuration 1s^(2) 2s^(2) 2p^(3) because the electrons would be closer to the nucleus yet 1s^(7) is not observed because it violates ?

STATEMENT-1: The ground state electronic configuration of nitrogen is STATEMENT-2: Electronic are filled in orbitals as per aufbau principle, Hund's rule of maximum spin multiplicity and pauli's principle.