The rms value of an ac of `50 Hz` is `10 A`. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be

The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be

The root-mean-square value of an alternating current of 50 Hz frequency is 10 ampere. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

The rms value of an alternating current

The time required for a 50Hz alternating current to increase from zero to 70.7% of its peak value is-

The frequency of an alternating current is 50 Hz . The minimum time taken by it is reaching from zero to peak value is

The peak value of an alternating current is 10. A. Find its rms value

An alternating voltage v(t)=220 sin 100pit volt is applied to a pureluy resistive load of 50Omega . The time taken for the current to rise from half of the peak value to the peak value is :

The electric current in an AC circuit is given by I=I_(0)sin omegat .What is the time taken by the current to change from its maximum value to the rms value?

The time required for a 50 Hz sinusoidal alternating current to changed its value from zero to the r.m.s. value

A resistance of 20 Omega is connected to a source of alternating current rated 110 V, 50 Hz . Find (a) the rms current, (b) the maximum instantaneous current in the resistor and (c) the time taken by the current to change from its maximum value to the rms value.