The conversion of a moving coil galvanometer into a voltmeter is done by
(a) introducing a resistance of large value in series.
(b) introducing a resistance of small value in parallel.
(c) introducing a resistance of large value in parallel.
(d) introducing a resistance of small value in series.

The resultant resistance of two resistance in series is 50 Omega and it is 12 Omega , when they are in parallel. The individual resistances are

The resistance of a series combination of the resistance is S. when they are joined in parallel equvalent resistance is P. Find the value of ((S)/(2P))

Out of five resistance of ROmega each 3 are connected in parallel and are joined to the rest 2 in series. Find the resultant resistance.

The senstivity of a galvanometer that measures current is decreased by 1/40 times by using shunt resistance of 10Omega . Then, the value of the resistance of the galvanometer is

Assertion : Voltmeter is connected in parallel with the circuit Reason : Resistance of a voltmeter is very large.

The Total resistance when connected in series in 9 Omega and when connected in parallel is 2 Omega The value of two resistance are

(a) Briefly explain how a galvanometer is converted into a voltmeter. (b) A voltmeter of a certain range is constructed by connecting a resistance of 980 Omega in series with a galvanometer. When the resistance of 470 Omega is connected in series, the range gets halved. Find the resistance of the galvanometer.

Assertion : A resistance wire is broken into four pices and all are connected in parallel. Then, net resistance becomes 1/16 times. Reason : In parallel net resistance is less than the smallest value of individual resistance.

The resultant resistance value of n resistance each of r ohms and connected is series is X. When those n , resistance are connected in parallel , the resultant values is .

The resistance of the series combination of two resistances is S. When they are joined in parallel the total resistance is P. If S= nP then the minimum possible value of n is