A particle performing S.H.M. undergoes displacement of `A/2` (where A = amplitude of S.H.M.) in one second. At `t = 0` the particle was located at either extreme position or mean position. The time period of S.H.M. cannot be: (consider all possible cases)

Define amplitude of S.H.M. ?

A particle performing simple harmonic motion undergoes unitial displacement of (A)/(2) (where A is the amplitude of simple harmonic motion) in 1 s. At t=0 , the particle may be at he extreme position or mean position the time period of the simple harmonic motion can be

Define amplitude of S.H.M. ? Does Amplitude affect the time period ?

A particle is performing S.H.M. Its total energy ie E When the displacement of the particle is half of its amplitude, its K.E. will be

A particle moves along x-axis according to relation x= 1+2 sin omegat . The amplitude of S.H.M. is

A particle executes S.H.M with time period 12 s. The time taken by the particle to go directly from its mean position to half its amplitude.

Two particles are performing SHM with same amplitude and time period. At an instant two particles are having velocity 1m//s but one is on the right and the other is on left of their mean positiion. When the particles have same position there speed is sqrt(3)m//s . Find the maximum speed (in m/s) of particles during SHM.

A particle performs SHM with an amplitude of 5 m. If at x = 4 m, the magnitude of velocity and accelertion are equal, then the time period of SHM (in seconds) is

A particle executes SHM with a frequency of 25 vib/s and has an amplitude of 0.02m. The speed of the particle 0.30 seconds after it is in the equilibrium position is (n pi )m/s. Find value of n

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes. At particular instant, one particle is at its extreme position while the other is at its mean position. The move in the same direction. They will cross each other after a further time.