A force `bar(F ) = ( 4hati - 3hatj + 5hatk )` N moves a body from `( 3hati + 6hatj + 3hatk ) ` m to `( ahati - 8hatj + 5hatk )`, If work done by the force is 8j then the value of a is

A particle acted upon by constant forces 4hati +hatj- 4 hatk and 3hati + hatj - hatk is displacment from the point hati+ 2hatj+ hatk to point 5hati + 4hatj +hatk .Total work done by the forces in SI unit is :

Under a force ( 10 hati - 3 hatj + 6 hatk) newton a body of mass 5 kg moves from position ( 6 hati + 5 hatj - 3 hatk) m to position ( 10 hati - 2hatj+ 7hatk) m . Deduce the work done.

A force vecF=10hati+2hatj+3hatk N displaces a particle from vecr_1=2hati+hatj+hatk m to vecr_2=4hati+2hatj+3hatk m Find the work done by the force.

A force (vecF) = 3 hati + c hatj + 2 hatk acting on a partical causes a displacement: (vecs) = - 4 hati + 2 hatj + 3 hatk in its own direction . If the work done is 6 j , then the value of c is

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

For what value of a, the vector s (2hati - 3hatj + 4hatk) and (ahati + 6hatj - 8hatk) collinear ?

If a force of (8.0 hati+2.0 hatj+3 hatk)N displaces a body through a distance of (6.0 hati-3 .0 hatj -9 hatk) m . The work done will be