Prove that `sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`

Prove that (a) sin^(2)(pi/6) + cos^(2)( pi/3) - tan^(2)(pi/4) = -1/2 (b) sin((8pi)/3) cos((23pi)/6) + cos((13pi)/3) sin((35pi)/6) = 1/2

Prove that : tan^2 (pi/4)+tan^2(pi/4)+tan^2(pi/3)=13/3

Find the value of the sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is:

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is:

Prove that: 2sin^(2)(pi)/(6)+csc^(2)(7 pi)/(6)cos^(2)(pi)/(3)=(3)/(2)

What is sin^2(3pi)+cos^2(4pi)+tan^2(5pi) equal to?

Prove that: (a) 2sin^(2)(pi/2) + "cosec"^(2)((7pi)/2) cos^(2)(pi/3)=(3/2)^2 (b) 2sin^(2)((3pi)/4)+2cos^(2)(pi/4)+2sec^(2)(pi/3)=10

Prove that: 2sin^(2)(3(pi)/(4))+2cos^(2)((pi)/(4))+2sec^(2)((pi)/(3))=10

Prove that 3"cos"^2 (pi)/(4)+sec^(2)(pi/3)+5 "tan"^(2)(pi)/(3)=(41)/(2) .