The work done in raising a body of mass m to a height `3R_(e)` above the earth's surface will be - `(R_(e)` is radius of earth)
(A) `4mgR_(e)`
(B) `3mgR_(e)`
(C) `(3)/(4)mgR_(e)`
(D) `(4)/(5)mgR_(e)`

A body of mass m is situated at a distance 4R_(e) above the earth's surface, where R_(e) is the radius of earth. How much minimum energy be given to the body so that it may escape

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

The change in the gravitational potential energy when a body of a mass m is raised to a height nR above the surface of the earth is (here R is the radius of the earth)

Find the change in the gravitational potential energy when a body of mass m is raised to a height nR above the surface of the earth. (Here, R is the radius of the earth)

If a body of mass m is raised to height 2 R from the earth s surface, then the change in potential energy of the body is (R is the radius of earth)

With what velocity must a body be thrown from earth's surface so that it may reach a maximum height of 4R_(e) above the Earth's surface ? (Radius of the Earth R_(e)=6400 km,g=9.8 ms^(-2) ).

The minimum projection velocity of a body from the earth's surface so that it becomes the satellite of the earth (R_(e)=6.4xx10^(6) m) .

A body of mass m is placed on the surface of earth. Find work required to lift this body by a height (i). h=(R_(e))/(1000) (ii). h=R_(e)

The gravitational potential energy of body of mass 'm' at the earth's surface - mgR_(e) . Its gravitational potential energy at a height R_(e) from the earth's surface will be (here R_(e) is the radius of the earth)

The escape velocity of a sphere of mass m is given by (G= univesal gravitational constant, M_(e) = mass of the earth and R_(e) = radius of the earth)