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The ionization enthalpy of Na^(+) format...

The ionization enthalpy of `Na^(+)` formation from `Na_((g))` is `495.8kJmol^(-1)`, while the electron gain enthalpy of `Br` is `-325.0kJmol^(-1)`. Given the lattice enthalpy of `NaBr` is `-728.4kJmol^(-1)`. The energy for the formation of `NaBr` ionic solid is `(-)` ____ `times10^(-1) kJmol^(-1)`

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