Solve `lim_(x->0) sin(1-x)/(1-x)`

lim_(x->oo)sin(1/x)/(1/x)

lim_(x->0) (sin x /x)

lim_(x rarr0)(sin^2x)/(1-cosx)

Evalute [lim_(xto0) (sin^(-1)x)/(x)]=1 , where [*] represets the greatest interger function.

Solve lim_(x to0)(1-cos(1-cosx))/(sin^(4)x)

The value of lim_(xrarr0) (x^2sin((1)/(x)))/(sinx) , is

Solve lim_(xto0)["sin"(|x|)/x] , where e[.] denotes greatest integer function.

lim_(x->0)(1/(x^2)-1/(tan^2x))

lim_(x rarr0)(1/x)^(1-cos x)

The value of lim_(x->0)((sinx-tanx)^2-(1-cos2x)^4+x^5)/(7(tan^(- 1)x)^7+(sin^(- 1)x)^6+3sin^5x) equal to :