Electric field associated with an electromagnetic wave in vacuum is given by E=E0 sin(`omega`t-Kz ) `hati` The value of magnetic field associated with same wave is (C is the speed of light in vaccum )

The electric and magnetic field of an electromagnetic wave is

Electric field of an electromagnetic wave vecE = E_0 cos (omegat-kx)hatj . The equation of corresponding magnetic field at t=0 should be

The electric field of a plane electromagnetic wave is given by vecE=E_(0)(hatx+haty)sin(kz-omegat) Its magnetic field will be given by :

The electric field of a plane electromagnetic wave is given by vec(E)=E_0haticos(kz)cos(omegat) The corresponding magnetic field vec(B) is then given by :

The electric field associated with an electromagnetic wave in vacuum is given by vecE=40cos(kz-6xx10^(8)t)hati, where E, z and t are in volt per meter, meter and second respectively. The value of wave vector k is

The electric field associated with an electromagnetic wave in vacuum is given by vecE=40cos(kz-6xx10^(8)t)hati, where E, z and t are in volt per meter, meter and second respectively. The value of wave vector k is

The electric field of an electromagnetic wave travelling through vacuum is given by the equation E = E_(0) "sin"(kx - omegat) The quantity that is independent of wavelength is

The electric vector vibration of an electromagnetic wave is given by E = (50NC^(-1)) sin omega(t-(x)/(c)) , The intensity of the wave is

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_0=510 nT . What is the amplitude of the electric field part of the wave?

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_0=510 nT . What is the amplitude of the electric field part of the wave?