A reversible heat engine converts one fourth of the heat input into work . When the temperature of the sink is reduced by 52 K , its efficiency is doubled . The temperature in Keelvin of the source will be

A reversible engine converts one-sixth of heat input into work. When the temperature of sink is reduced by 62^(@)C, its efficiency is doubled. Find the temperature of the source and the sink,

A Carnot reversible engine converts 1//6 of heat input into work. When the temperature of the sink is redused by 62 K, the efficiency of Carnot’s cycle becomes 1//3 . The sum of temperature (in kelvin) of the source and sink will be

An engine has an efficiency of 1/6 . When the temperature of sink is reduced by 62^(@)C , its efficiency is doubled. Temperature of the source is

An engine has an efficiency of 1/6 . When the temperature of sink is reduced by 62^(@)C , its efficiency is doubled. Temperature of the source is

An engine has an efficiency of 0.25 when temperature of sink is reduced by 58^(@)C , If its efficiency is doubled, then the temperature of the source is

A Carnot engine has an efficiency of 20% . When temperature of sink is reduced by 80°C its efficiency is doubled. The temperature of source is

A Carnot engine has an efficiency of 1//6 . When the temperature of the sink is reduced by 62^(@)C , its efficiency is doubled. The temperature of the source and the sink are, respectively.

A beat engine work on a Cannot cycle with the heat sink in the temperature of 27^(@)C . IF the efficiency is 20%, then the temperature (in Kelvin) of the heat source will be

A Carnot engine efficiency is equal to 1/7 . If the temperature of the sink is reduced by 65 K , the efficiency becomes 1/4 . The temperature of the source and the sink in the first case are respectively

An engine takes heat from a reservior and converts its 1//6 part into work. By decreasing temperature of sink by 62^(@)C , its efficiency becomes double. The temperatures of source and sink must be