`(1-x^2)dy/dx+2xy=(1-x^2)`

(1-x^(2))(dy/dx)+xy=xy^(2)

(1-x^(2))(dy)/(dx)-xy=1

(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2));y=0 if x=1

Find the particular solution of the differential equation (1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2)) given that y=0 when x=1

The differential equations,find a particular solution satisfying the given condition: (1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2));y=0 when x=1

Find the particular solution of the differential equation (1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2)) given that at x=1 , y=0 .

The solution of (1-x^2) dy/dx+2xy-xsqrt(1-x^2)=0 , is (A) y/((1-x^2))=1/sqrt(1-x^2)+C (B) y(1-x^2)=sqrt(1-x^2)+C (C) y(1-x^2)^(3/2)=sqrt(1-x^2)+C (D) none of these

(1-x^(2))(dy)/(dx)-2xy=x-x^(3)

(1-x^(2))(dy)/(dx)-xy=x^(2)