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Std 8 gujarati ch 10 swadhyaypothi solut...

Std 8 gujarati ch 10 swadhyaypothi solution

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The [OH] in a solution is 1xx10^(8) . The pH of the solution is

20 mol of M//10 CH_(3)COOH solution is titrated with M//10 NaOH solution. After addition of 16 mL solution of NaOH . What is the pH of the solution (pK_(a) = 4.74)

A solutions is 10 M in CH_(3)COONa and 1 M in CH_(3)COOH . If pK_(a) of CH_(3)COOH is 4.8 , what is the pH of the solution?

A solution is 10 M in CH_(3)COONa and 1 M in CH_(3)COOH . If pK_(a) of CH_(3)COOH is 4.8 , what is the pH of the solution?

A solution is 1M in CH_(3)COONa . and 0.1M in CH_(3)COOH . if pK_(a) of CH_(3)COOH is 4.8 , what is the pH of the solution?

Calculate the change in pH if 0.02 mol CH_(3)COONa is added to 1.0L of this solution. ltbRgt K_(a) of CH_(3)COOH = 1.8 xx 10^(-5) .

1 M solution of CH_(3)COOH is diluted to x times so that pH of solution is doubled. Calculate x Given K_(a)=1.8xx10^(-5)

For a reaction, CH_(3)COOH(aq) hArr H^(+) (aq)+CH_(3)COO^(-)(aq) or HAc (aq) hArr H^(+)(aq)+Ac^(-)(aq) Evaluate the pH of the solution resulting on addition of 0.05M acetata ion to 0.05M acid solution (K_(a) = 1.8 xx 10^(-5))