The ratio of energy required to accelerate a car from rest to `20ms^(-1)` to the energy needed to accelerate from `20ms^(-1)` to `40ms^(-1)` is

A) 1 : 1

B) 1 : 3

C) 1 : 2

D) 1 : 4

The energy required to accelerate a car from 10 m/s to 20 m / s is how many times the energy required to accelerate the car from rest to 10 m /s

What force should be applied on a body of mass 500 kg to change its velocity from 4 ms^(1) to 6 ms^(-1) in one second ?

A particle starting from rest attains a velocity of 50 ms^(-1) in 5 s. The acceleration of the particle is

A boy is running over a circular track with uniform speed of 10 ms^(-1) . What is the average velocity for movement of boy from A to B (in ms^(-1) ) ?

How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to 20 ms^(-1) is 10 s?

A particle moves in a circle of radius 4 m with a linear velocity of 20ms^(-1) . Find the angular velocity.

One of the rectangular components of a velocity of 20 ms^(-1) is 10 ms^(-1) . Find the other component.

A car is moving with uniform acceleration along a straight line between two stops X and Y. Its speed at X and Y are 2 ms^-1 and 14 ms^-1 , Then

A body starts at t=0 with velcoity u and travels along a straight linge. The body has a constant acceleration(a). Draw the acceleration-time graph from t=0 to t=10 s for the following cases: a. u=8 ms^(-1) , a=2s^(-2) b. u=8 ms^(-1) , a=-2 ms^(-2) c. u=- 8ms^(-1) ,a=2 ms^(-2) d. u=-8ms^(-1) ,a=-2 ms^(-2) .

A particle's velocity changes from (2hat I +3 hatj) ms^(-1) in to (3 hati - 2hatj) ms^(-1) in 2s. Its average acceleration in ms^(-2) is