A `2` MeV proton is moving perpendicular to a uniform magnetic field of `2.5T` .The force on the proton is `8times10^(n)` N where `n` is

A proton of energy 2 MeV is moving perpendicular to uniform magnetic field of 2.5T . The form on the proton is (Mp=1.6xx10^(-27)Kg and q=e=1.6xx10^(-19)C)

Particles 1, 2 and 3 are moving perpendicular to a uniform magnetic field, then particle

If a charged particle is a plane perpendicular to a uniform magnetic field with a time period T Then

A proton is moved along a magnetic field line.The magnetic force on the particle is

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

If a proton is projected in a direction perpendicular to a uniform magnetic field with velocity v and and electron is projected along the line of force, what will happen to proton and electron?

A proton and an alpha particle move in circular paths in a plane perpendicular to a uniform magnetic field. If the kinetic energy of the two particles is equal, the ratio of the radii of their paths is _________.

A proton of energy 8 eV is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be

Assertion When a charged particle moves perpendicular to a uniform magnetic field then its momentum remains constant. Reason Magnetic force acts perpendicular to the velocity of the particle.

A proton is moving along Z -axis in a magnetic field. The magnetic field is along X -axis. The proton will experience a force along