Find the equation of the normal to the curve `y=sinx` at the point `(pi,0)`

The equation of the normal to the curve y=sin x at the point (pi,0) is: O x+y=pi O x+y+pi=0 O x-y=pi O x-y+n=0

The equation of the normal to the curve y=x(2-x) at the point (2, 0) is

The equation of the normal to the curve y=sin x at (0,0) is

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

Find the equation of the normal to the curve a y^2=x^3 at the point (a m^2,\ a m^3) .

Find the equation of the normal to the curve ay^(2)=x^(3), at the point (am^(2),am^(3)). If normal passes through the point (a,0) then find the slope.

Find the equation of the tangent to the curve y=sec x at the point (0,1)

Find the equation of the normal to curve y^(2)=4x at the point (1, 2) .

The equation of normal to the curve y = tan x at the point (0, 0) is

The equation of the normal to the curve y^2=4ax at point (a,2a) is