`cot(A+B)=(cotA.cotB-1)/(cotB+cotA)`

If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)

If A+B+C=pi , prove that : (cotB+cotC) (cotC+cotA) (cotA+cotB)=cosecA cosecB cosecC

Prove that (cotA- cosA)/(cotA+ cosA) = (cosecA -1)/(cosecA+1)

Prove that (cotA-cosA)/(cotA+cosA)=(cosecA-1)/(cosecA+1)

(cosec A. cosecB+cotA . cotB)^2-(cosec A. cotB + cosecB. cot A)^2 is

If A+B+C=pi , prove that : (cotA+cotB)/(tanA+tanB) + (cotB+cotC)/(tanB+tanC) + (cotC+cotA)/(tanC+tanA) =1

Prove: (cotA+tanB)/(cotB+tanA)=cotAtanB

Prove that (cotA+tanB)/(cotB+tanA)=cotAtanB

In a triangle ABC, prove that (cot(A/2)+cot(B/2)+cot(C/2))/(cotA+cotB+cot(C))=((a+b+c)^2)/(a^2+b^2+c^2)

Prove that cosA=(cotA)/("cosec A")=(cotA)/(sqrt((1+cot^(2)A)))" "(A in" III quad.")