Find out the molar specific heat `C_p` and `C_v` of an ideal gas having y=1.67, given R=2 cal `mol^-1^@ c^-1`

Find out the molar specific heat C_p and C_v of an ideal gas having gamma =1.67, given R=2 cal mol^-1^@ c^-1

Find out the molar specific heats C_(p) an C_(v) of an ideal gas having gamma = 1.67 . Given, R = 2 cal cdot mol^(-1) cdot^(@)C^(-1) .

The molar specific heats C_(p) and C_(v) of an ideal gas are expressed in the unit of cal cdot mol^(-1) cdot^(@)C^(-1) . But R is expressed in J cdot mol^(-1) cdot^(@)C^(-1) . Write down the relation between C_(p) and C_(v) .

The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C . (ii) At constant pressure. Find out the amount of heat supplied and the rise in internal energy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1) .

For an ideal gas, gamma = 1.4 . Find out the two molar specific heats of this gas. [R = 2 cal cdot mol^(-1) cdot^(@)C^(-1)]

A gas of density 0.00125 g cdot cm^(3) , volume 8L at 0^(@)C temperature and 1 atm pressure is supplied with 30 cal of heat to raise its temperature to 15^(@)C at constant pressure. Determine the specific heat of the gas at constant pressure and at constant volume. Given, R = 2 cal cdot mol^(-1) cdot^(@)C^(-1) .

From the relation C_p-C_v=R show that the ratio of two specific heats (gamma) of an ideal gas is given by gamma=1+2/f where f is the degrees of freedom of the molecule.

From the relation C_p - C_v= R show that the ratio of two specific heats (gamma) of an ideal' gas is given by gamma = 1+ 2/ f , where f is the degrees of freedom of a molecule.

What will be the change in internal energy of 128 g of oxygen gas at constant volume when it is heated from 30^(@)C to 45^(@)C ? The molar specific heat of oxygen at constant pressure is C_(p) = 7.03 cal cdot mol^(-1) cdot^(@)C^(-1) and R = 8.31 J cdot mol^(-1) cdot^(@)C^(-1) .