If the energy of incident photon and work function of a metal are E, ϕ respectively, then the maximum velocity of emitted photo electrons will be(take m as the mass of electron

Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

Two photons of energies twice and thrice the work function of a metal are incident on the metal surface .Then, the ratio of maximum velocities of the photoelectrons emitted in the two cases respectively ,is

Radiations of two photon’s energy, twice and ten times the work function of metal are incident on the metal surface successsively. The ratio of maximum velocities of photoelectrons emitted in two cases is

For photoelectric emission from certain metal the cut - off frequency is v . If radiation of frequency 2 v incident on the metal plate , the maximum possible velocity of the emitted electron will be ( m is the electron mass).

Radiation two photons having energies twice and five times the work function of a metal are incident successively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted in the two cases will be

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV . The minimum kinetic energy of the emitted photo - electrons will be

A light of intensity 16 mW and energy of each photon 10 eV incident on a metal plate of work function 5 eV and area 10^(-4)m^(2) then find the maximum kinetic energy of emitted electrons and the number of photoelectrons emitted per second if photon efficiency is 10% .

Monochromatic photons of energy 3.3 eV are incident on a photo sensitive surface of work function 2.4 eV. , maximum velocity of photoelectron is

Photoelectric threshold of silver is lamda=3800A . Ultraviolet light of lamda=2600A is incident of a silver surface. Calculate: a. the value of work function in joule and in eV. b. maximum kinetic energy of the emitted photoelectrons. c. the maximum velocity of the photoelectrons. (Mass of the electrons =9.11xx10^(-31) ).

Photoelectric threshold of silver is lamda=3800A . Ultraviolet light of lamda=2600A is incident of a silver surface. Calculate: a. the value of work function in joule and in eV. b. maximum kinetic energy of the emitted photoelectrons. c. the maximum velocity of the photoelectrons. (Mass of the electrons =9.11xx10^(-31) ).