If `b>a>0` and `c>0` , then `(a+c)/(b+c)>a/b`

If a+b+c= 0 , then (a+b)/(c ) = ?

If a,b,c gt 0, then (a )/(b +c) = (b)/( c +a) = (a)/(a +b) = ?

If a,b,c gt 0, then (a )/(2a + b +c ) = (b)/(a + 2b +c)= (c )/(a +b + 2c) = ?

If a b c = 0, then ({(x^a)^b}^c)/({(x^b)^c}^a) = (a)3 (b) 0 (c) -1 (d) 1

If a+b+c= 0 , then ((a+b)/(c ) + (b+c)/(a) + (c+ a)/(b)) ((c )/(a+b) + (b)/(a+c) + (a)/(b+c)) = ?

If a+b+c= 0 , then (a+b)/(c ) + (b+c)/(a) + (c +a)/(b) = ?

If a+b+c= 0 , then (c )/(a+b) + (b)/(a+c) + (a)/(b + c) = ?

If a,b,c gt 0 then (a)/( a + b + c) = (b)/( a + b + c) = (c )/(a + b + c) = ?

If a>0,b>0,c>0 prove that a/(b+c)+b/(c+a)+c/(a+b)ge3/2 .

If f(x)=|ax-b|+c|x| is stricly increasing at atleast one point of non differentiability of the function where a>0,b>0,c>0 then (A) c>a( B) a>c(C)b>a+c(D)a=b