The area of a trapezium is defined by function `f` and given by `f(x)=(10+x)sqrt(100-x^2)`, then the area when it is maximised is:
\ a) `75cm^2`
b) `7sqrt3cm^2`
c) `75sqrt3cm^2`
d) `5cm^2`

The area of a trapezium is defined by function ? and given by f(x) =(10+x) sqrt(100-x^(2)) , then the area when it is maximised is:

1.The area of a trapezium is defined by function f and given by f(x) = (10 + x) √ (100 - x^2) , then the area when it is maximised is: a). 75 cm^2 b). 7 √3 cm^2 c). 75 √3 cm^2 d). 5 cm^2

If f(x)=sqrt(2x-3)+sqrt(7-3x) ,then the value of f'(2) is?

The three sides of a trapezium are equal, each being 8cm. The area of the trapezium, where it is maximum, is (a)24sqrt(3) c m^2 (b) 48sqrt(3)c m^2 (c)72sqrt(3)c m^2 (d) none of these

In the adjoining figure, the length of BC is (a) 2sqrt3 cm (b) 3sqrt3 cm (c) 4sqrt3 cm (d)3 cm

The area of the isosceles triangle is (5)/(4)sqrt11cm^(2) if the perimeter is 11 cm and the base is 5 cm.

What is the area (in cm^2) of a regular hexagon of side 9 cm is equal to ? (A) 50sqrt3cm^2 (B) 300sqrt3cm^2 (C) 243sqrt3/2cm^2 (D) 200sqrt3cm^2

The sides of a triangle are 16cm,30cm and 34cm. Its area is 225cm^(2) (b) 225sqrt(3)cm^(2)225sqrt(2)cm^(2)(d)450cm^(2)

A square and an equilateral triangle have equal perimeters.If the diagonal of the square is 12sqrt(2)cm ,then area of the triangle is: 24sqrt(2)cm^(2) (b) 24sqrt(3)cm^(2)48sqrt(3)cm^(2) (d) 64sqrt(3)cm^(2)