A beam of light from the point `A(3,10)` reflects from the line `2x+y-6=0` and then passes through the point `B(5,6)`. The equation of reflected beam is:

A light beam emanating from the point A(3,10) reflects from the straight line 2x+y-6=0 and then passes through the point B(4,3) .The equation of the reflected beam is x+3y-lambda=0, then the valueof lambda is

A light beam, emanating from the point (3, 10) reflects from the straight line 2x+y-6=0 and then passes through the point B(7, 2) . Find the equations of the incident and reflected beams.

A ray of light passing through the point A(2,3) reflected at a point B on line x+y=0 and then passes through (5,3). Then the coordinates of B are

A ray of light is sent through the point P(1,2,3) and is reflected on the XY plane. If the reflected ray passes through the point Q(3,2,5) then the equation of the reflected ray is

A ray of light passing through the point (1,2) reflects on the xaxis at point A and the reflected ray passes through the point (5,3) . Find the coordinates of A.

A ray of light through (2,1) is reflected at a point P on the y-axis and then passes through the point (5,3). If this reflected ray is the directrix of an ellipse with eccentricity (1)/(3) and the distance of the nearer focus from this directrix is (8)/(sqrt53) , then the equation of the other directrix can be

A ray of light passing through the point P(1,2) reflects on the x-axis at the point A and the reflected ray passes through the point Q(5,3). Find the coordinates of the point A

A ray of light passing through the point (1,2) reflects on the x-axis at point A and the reflected ray passes through the point (5,3) Find the co-ordinates of A.