An Indian rubber cord 12 cm long is suspended vertically . How much does it stretch (in mm ) . underits own weight (young modulus of rubber is `5 times 10^6`N//``m^2` ,g=10m/`s^2` `rho= 1.5 g/`cm^3`

A rubber cord 10 m long is suspended vertically. How much does it stretch under its own weight (Density of rubber is 1500 kg//m, Y=5xx10 N//m,g = 10 m//s )

A rubber cord of density d, Young's modulus Y and length L is suspended vertically . If the cord extends by a length 0.5 L under its own weight , then L is

An indian ruber cord L meter long and area of cross-secion A metre is suspended vertically. Density of rubber is rho kg/ "metre"^(3) and Young's modulus of rubber is Y newton/ "metre"^(2) . IF the cord extends by l metre under its own. Weight, then extension l is

A disc of mass 1 kg and radius 10 cm is suspended by vertical wire at its centre. If the time period is 3.2 s. Find the modulus of torison.

A rod of uniform cross sectional area 5mm^2 weighing 5 kg and length 1 m is suspended vertically from a fixed support the elongation produced in the rod if [Young's modulus of material, Y=2 x 10^11 N/m^2 and g=10 ms^(-2) ]

The breaking stress for a substance is 10^(6)N//m^(2) . What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire =4xx10^(3)kg//m^(3) and g=10 ms^(-2))

A rubber rope of length 8 m is hung from the ceiling of a room. What is the increase in length of rope due to its own weight? (Given: Young's modulus of elasticity of rubber = 5 xx 10^(6) N//m and density of rubber =1.5xx10^(3)kg//m^(3) . Take g=10ms^(-12))

The breaking stress for a substance is 10^(6)N//m^(2) . What length of the wire of this substance should be suspended verticaly so that the wire breaks under its own weight? (Given: density of material of the wire =4xx10^(3)kg//m^(3) and g=10 ms^(-12))

When a rubber ball is taken to the bottom of a sea of depth 1400 m the volume decreases by 2% . The Bulk modulus of rubber ball is (density of water is 1g//cm^3 and g =10 m//s^2

A wire 2 m in length suspended vertically stretches by. 10 mm when mass of 10 kg is attached to the lower end. The elastic potential energy gain by the wire is (take g = 10 m//s^(2) )