Two particle of same mass are revolving in two horizontal circles of radii in the ratin 1:2 . In order to experince same centripetal force , the ratio of their speed is

Two particles of same mass are revolving in circular paths having radii r_(1) and r_(2) with the same speed. Compare their centripetal forces.

Two particles of masses in the ratio 1: 2 you're moving in circles of radii in the ratio 2:3 with time periods in the ratio 3: 4. The ratio of their centripetal forces is

A particle of mass m is revolving in a horizontal circle of radius r under a centripetal force k//r^(2) where k is a constant. What is the total energy of the particle ?

Two particles of equal masses are revolving in circular paths of radii, r_(1) and r_(2) respectively with the same period . The ratio of their centripetal force is -

Two particles each of mass m are moving in horizontal circle with same angular speed. If both string are of same length then the ratio of tension in string (T_(1))/(T_(2)) is

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is

Two particles of equal masses are revolving in circular paths of radii r_(1) and r_(2) respectively with the same speed. The ratio of their centripetal force is

A particle of mass m is moving in a horizontal circle of radius R under a centripetal force equal to -A/r^(2) (A = constant). The total energy of the particle is :- (Potential energy at very large distance is zero)

If the radii of circular path of two particles are in the ratio of 1 :2 , then in order to have same centripetal acceleration, their speeds should be in the ratio of :

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -