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FLUID DYNAMICS + NCERT Qs

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DYNAMIC LIVING ENTITY

In Fig. 6.55, QS ⊥ PR, RT ⊥ PQ and QS = RT. (i) Is ∆ QSR ≅ ∆ RTQ ? Give reasons. (ii) Is ∠ PQR = ∠ PRQ ? Give reasons.

How To Reduce Friction ?|Types Of Friction|Fluid Friction|NCERT Exercise|OMR

Body Fluids And Circulation /Class 11/NCERT/Chapter 18/Quick Revision Series/NEET/AIIMS/JIPMER/

In quadrilateral PQRS, RM bot QS, PN bot QS and QS = 6cm. If RM = 3 cm and PN = 2 cm, then the area of PQRS is: चतुर्भुज PQRS में, RM bot QS, PN bot QS तथा QS = 6 सेमी है | यदि RM = 3 सेमी तथा PN = 2 सेमी है, तो PQRS का क्षेत्रफल कितना होगा ?

In the given figure, QS bot PR, RT bot PQ and QS =RT Is triangleQSR =~ triangleRTQ ? Give reason. (ii) Is anglePQR = anglePRQ ? Give reason.

trianglePQR, angleQ=90^(@), PQ=12, QR=5, QS is a medium find l(QS).

PQRS is a parallelogram in which PR is perpendicular to QS. If PR=8cm and QS=6 cm, then find PS