Two stones of mass m and 2m are projected vertically upward so to reach the same height. The ratio of their kinetic energies of projection is 1:N. The value of N is :

A stone is projected vertically upward to reach maximum height h. The ratio of its kinetic energy to its potential energy at a height (4)/(5) h, will be

A particle A is projected verically upwards. Another indentical particle B is projected at an angle of 45^(@) . Both reach the same height. The ratio of the initial kinetic energy of A to that of B is -

A particle A is projected verically upwards. Another indentical particle B is projected at an angle of 45^(@) . Both reach the same height. The ratio of the initial kinetic energy of A to that of B is -

If two particles of masses m_(1) and m_(2) are projected vertically upwards with speed v_(1) and v_(2) , then the acceleration of the centre of mass of the system is

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be

A stone of mass 0.4 kg is projected vertically upward through a height 10 m. if g=10 ms^(-2) , calculate the potential energy of the stone at the highest point.

With what velocity a body of mass m be projected vertically upwards so that it may be able to reach a height nR above earth's surface

A body of mass m thrown vertically upwards attains a maximum height h. At height will its kinetic energy be 75% of its intial value?

Two balls of different masses are thrown vertically upwards with the same speed . They pass through the point of projection in their downward motion with the same speed ( Neglect air resistance ).

A stone projected vertically upwards from the ground reaches a maximum height h . When it is at a height (3h)//(4) , the ratio of its kinetic and potential energies is