Home
Class 12
PHYSICS
Stopping potential are V(1) and V(2) .Th...

Stopping potential are `V_(1)` and `V_(2)` .The value of `(V_(1)-V_(2))` ,if `lambda_(1)` and `lambda_(2)` are wavelengths of incident lights respectively is

Promotional Banner

Similar Questions

Explore conceptually related problems

A plenet moving along an elliptical orbit is closest to the sun at a distance r_(1) and farthest away at a distance of r_(2) . If v_(1) and v_(2) are the linear velocities at these points respectively, then the ratio (v_(1))/(v_(2)) is

The work function of Cs is 2.14 ev find the wavelength of the incident light if the stopping potential is 0.6 V.

The graph between the stopping potential (V_(0)) and ((1)/(lambda)) is shown in the figure phi_(1) , phi_(2) and phi_(3) are work function , which of the following is /are correct

V_(1) and V_(2) are the stopping potentials for the incident radiations of wave lengths lamda_(1) and lamda_(2) respectively are incident on a metallic surface. If lamda_(1)=3lamda_(2) then

Two capacitors with capacities C_(1) and C_(2) ,are charged to potentials V_(1) and V_(2) respectively.When they are connected in parallel,the ratio of their respective charges is ....?

Stopping potential of emitted photo electron is V when monochromatic light of wavelength 'lamda' incident on a metal surface. If wavelength of light incident becomes 'lambda/3' stopping potential of photoelectrons becomes V/4 then the threshold wavelength of metal is k'lambda' then k will be

µ_(1) and µ_(2) are the refractive index of two mediums and v_(1) and v_(2) are the velocity of light in these in two mediums respectively. Then, the relation connecting these quantities is

If lambda_(1) and lambda_(2) are the wavelength of the first members of the Lyman and Paschen series, respectively , then lambda_(1) :lambda_(2) is

In a photoelectric effect measurement, the stopping potential for a given metal is found to be V_(0) volt, when radiation of wavelength lamda_(0) is used. If radiation of wavelength 2lamda_(0) is used with the same metal, then the stopping potential (in V) will be

A dye absorbs a photon of wavelength lambda and re - emits the same energy into two phorons of wavelengths lambda_(1) and lambda_(2) respectively. The wavelength lambda is related with lambda_(1) and lambda_(2) as :