A periodic function is given as `sin ( omega t) + cos (omega t)` , the amplitude of this function is given by

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

The displacement of a particle performing simple harmonic motion is given by, x=8 "sin" "omega t + 6 cos omega t, where distance is in cm and time is in second. What is the amplitude of motion?

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

If i_(1)=3 sin omega t and (i_2) = 4 cos omega t, then (i_3) is

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

Find time period of the function, y=sin omega t + sin 2omega t + sin 3omega t

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be

The velocity of the particle of mass m as a function of time t is given by v = Aomega.cos[sqrt(K/m)t] , where A is amplitude of oscillation. The dimension of A/K is