A capacitor of capacitance 10 microfarad is charged to potential of 1000 V
1. Find energy stored in the capacitor
2. If a slab of dielectric constant K=5 , is introduced between the plates of the capacitor , such that is fully fills the space between the plates, then the new capacitance of the capacitor is :

A dielectric slab of relative premittivity (i.e. dielectric constant) 6 is introduced between the two plates of an 8 mu F air capacitor, in order to completely occupy the space between the two plates. Find the new capacitance of the capacitor.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

The potentials of the two plates of capacitor are +10V and -10 V . The charge on one of the plate is 40 C . The capacitance of the capacitor is

To reduce the capacitance of parallel plate capacitor, the space between the plate is

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

An air-cored parallel plate capacitor having a capacitance C is charged by connecting it to a battery. Now, it is disconnected from the battery and a dielectric slab of dielectric constant K is inserted between its plates so as to completely fill the space between the plates. Compare : (I) Initial and final capacitance (ii) Initial and final charge. (iii) Initial and final potential difference. (iv) Initial an final electric field between the plates. (v) Initial and final energy stored in the capacitor.

A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q' .