A 220V, 50 Hz ac source is connected to a series combination of a 3.16 micro farad capacitor , 0.63 H inductor and 600 ohm resistor.
Reactance of the inductor is

Answer

To find the reactance of the inductor in the given circuit, we can follow these steps:

### Step 1: Identify the given values
- Voltage (V) = 220 V (not needed for reactance calculation)
- Frequency (f) = 50 Hz
- Inductance (L) = 0.63 H

### Step 2: Calculate the angular frequency (ω)
The angular frequency (ω) is given by the formula:
\[ \omega = 2\pi f \]
Substituting the value of frequency:
\[ \omega = 2\pi \times 50 \text{ Hz} = 100\pi \text{ rad/s} \]

### Step 3: Calculate the reactance of the inductor (XL)
The reactance of the inductor (XL) is given by the formula:
\[ X_L = \omega L \]
Substituting the values of ω and L:
\[ X_L = (100\pi) \times 0.63 \]
Calculating this gives:
\[ X_L = 63\pi \text{ ohms} \]

### Step 4: Calculate the numerical value of XL
Using the value of π (approximately 3.14):
\[ X_L = 63 \times 3.14 \approx 197.82 \text{ ohms} \]

### Final Result
The reactance of the inductor is approximately:
\[ X_L \approx 197.82 \text{ ohms} \]

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