Bihar board Solutions part -2(crash course)

Evolution part2 |class 12

Profit and loss part-2

coordination part 2

Three suggestion are made for ways to removes silver ions from solution: a. Make the solution 0.01M in Nal . b. Buffer the solution at pH = 13 . c. Make the solution 0.01M Na_(2)S . What will be the equilibrium silver ion concentartion in each case? which course of action is most effective in removing Ag^(o+) ions? K_(sp) (AgI) = 8.5 xx 10^(-17), K_(sp) (AgOH) = 2 xx 10^(-8) , K_(sp) (Ag_(2)S) = 5.5 xx 10^(-51)

Study the diagram given alongside showing a plant cell kept in a strong sugar solution. Which part of the cell acts as a semipermeable membrane?

$ Soil solutIon is absorbed by all the parts of a root . ! Soil solution is always of a high concentration.

The number of solution of the equastion |x-1|+|x-2|=[{x}]+{[x]}+1 , where [.] and {.} denotes greatest integer function and fraction part funstion respectively is :

Given below is a diagram of the cell as seen number the microscope after having been placed in a solution. Name the parts numbered A to

The number of solutions of the equation cos ^(-1)((1-x ^(2) -2x)/((x+1) ^(2)))=pi (1- {x}, for x in[0,76] is equal to (where {.} denote fraction part function)