`int_(-1)^(1)[x[ 1+in pi x]dx=` where [.] represents greatest integer function.

The value of I = int_(-1)^(1)[x sin(pix)]dx is (where [.] denotes the greatest integer function)

The value of int_0^(2pi)[2 sin x] dx , where [.] represents the greatest integral functions, is

Evaluate: int_0^(10pi)[tan^(-1)x]dx ,w h e r e[x] represents greatest integer function.

Evaluate: int_0^(10pi)[tan^(-1)x]dx ,w h e r e[x] represents greatest integer function.

Evaluate: int_0^(100)x-[x]dx where [dot] represents the greatest integer function).

The integral I=int_(0)^(100pi)[tan^(-1)x]dx (where, [.] represents the greatest integer function) has the vlaue K(pi)+ tan(p) then value of K + p is equal to

Find x satisfying [tan^(-1)x]+[cot^(-1)x]=2, where [.] represents the greatest integer function.

Find x satisfying [tan^(-1)x]+[cos^(-1)x]=2, where [] represents the greatest integer function.

Find the domain and range of f(x)="sin"^(-1)(x-[x]), where [.] represents the greatest integer function.

Prove that [lim_(xto0) (tan^(-1)x)/(x)]=0, where [.] represents the greatest integer function.